Veteran shortstop Jimmy Rollins has agreed to a minor league contract with the San Francisco Giants that includes an invitation to major league spring training, Giants general manager Bobby Evans confirmed on Monday.
The deal will reportedly be worth $1 million if Rollins reaches the majors, according to Fox Sports’ Ken Rosenthal.
Rollins signed a minor league deal with the Chicago White Sox last winter, and won the starting job at shortstop for the team. He blasted a game-winning homer the day after opening day, but from there it went down hill.
Chicago released Rollins in June, after complying 33 hits in 149 at-bats for a .221/.295/.329 batting line that included 2 homers, 8 RBIs, and 5 stolen bases.
Rollins spent the first 15 years of his career with the Philadelphia Phillies. He was the winner of the 2007 National League MVP Award, and a four-time Gold Glove Award winner. Philadelphia dealt Rollins to the Los Angeles Dodgers, where he would play one season before his short stint in Chicago.
If Rollins makes the Giants opening day roster, he is more than likely going to be serving in a bench role, as the Giants are all set in the infield with Eduardo Nunez at third base, Brandon Crawford at shortstop, Joe Panik at second base, and Brandon Belt at first.
2017 will mark Rollins’ 18th year in the league, and he is only five career MLB hits behind Ozzie Smith. The 38-year-old Rollins is also currently sixth in terms of all-time games played by a shortstop. He trails Omar Vizquel, Derek Jeter, Luis Aparicio, Smith, and Cal Ripken.
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